Having a problem getting mysqli_query to execute [duplicate]

This ques开发者_JAVA技巧tion already has an answer here: What to do with mysqli problems? Errors like mysqli_fetch_array(): Argument #1 must be of type mysqli_result and such (1 answer) Closed 2 years ago.

Here's the problem: I started a swap today to use mysqli. No biggie, just had to change a few statements. Everything went fine, no errors... Except that I can't get it to execute any queries at all. I have double and triple checked my syntax. I even started creating situations where it SHOULD return an error (Trying to get it to INSERT to Tables that don't exist or with values that exceeded column limits or didn't match type) and... nothing. It doesn't return an error, it doesn't write. It WILL complain if parameter one is NOT a mysqli type.

Here's the relevant code:

$con = mysqli_connect("localhost", "root", "","test");

if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}

$query = "INSERT INTO files VALUES (NULL, 5, 'hello')";
mysqli_query($con, $query);

And nothing. It runs without a problem, but it never writes the record. I can even change the $query to "hdjhkfhhjfkd" and it runs no problem. mysqli_query() just isn't executing, period. The only time I can get it to react is if I change $con to anything else, then it complains that it needs a mysqli type.

Thoughts? THis is driving me bonkers.

---

Have you checked the return value of mysqli_query()? It returns FALSE if an error occurred. In that case mysqli_error() gives you more information about the error.

<?php
$con = mysqli_connect("localhost", "root", "", "test");
if (mysqli_connect_errno()) {
  printf("Connect failed: %s\n", mysqli_connect_error());
  exit();
}

$query = "INSERT INTO files VALUES (NULL, 5, 'hello')";
echo "<pre>Debug: $query</pre>\m";
$result = mysqli_query($con, $query);
if ( false===$result ) {
  printf("error: %s\n", mysqli_error($con));
}
else {
  echo 'done.';
}