Suppose I have 4 words, as a string. How do I join them all like this?
s = orange apple grapes pear
The result would be a String:
开发者_StackOverflow"orangeapple/orangegrapes/orangepear/applegrapes/applepear/grapespear/orangeapplegrapes/orangeapplepear/applegrapespear"
I am thinking:
list_words = s.split(' ')
for l in list_words:
And then use enumerate? Is that what you would use to do this function?
Maybe this is what you want?
s = "orange apple grapes pear"
from itertools import product
l = s.split()
r='/'.join(''.join(k*v for k,v in zip(l, x))
for x in product(range(2), repeat=len(l))
if sum(x) > 1)
print r
If run on 'a b c' (for clarity) the result is:
bc/ac/ab/abc
(Updated after comment from poster.)
>>> from itertools import combinations
>>> s = "orange apple grapes pear".split()
>>> '/'.join([''.join(y) for y in [ x for z in range(len(s)) for x in combinations(s,z)] if len(y)>1])
'orangeapple/orangegrapes/orangepear/applegrapes/applepear/grapespear/orangeapplegrapes/orangeapplepear/orangegrapespear/applegrapespear'
s = 'orange apple grapes pear'
list_words = s.split()
num = len(list_words)
ans = []
for i in xrange(1,2**num-1):
cur = []
for j,word in enumerate(list_words):
if i & (1 << j):
cur.append(word)
if len(cur) > 1:
ans.append(''.join(cur))
print '/'.join(ans)
This gives all subsets of the list of words except the empty one, single words, and all of them. For your example: orangeapple/orangegrapes/applegrapes/orangeapplegrapes/orangepear/applepear/orangeapplepear/grapespear/orangegrapespear/applegrapespear
>>> import itertools
>>> from itertools import combinations
>>> s = "orange apple grapes pear".split()
>>> res=[]
>>> for i in range(2,len(s)+1):
... res += [''.join(x) for x in combinations(s,i)]
...
>>> '/'.join(res)
'orangeapple/orangegrapes/orangepear/applegrapes/applepear/grapespear/orangeapplegrapes/orangeapplepear/orangegrapespear/applegrapespear/orangeapplegrapespear'
>>> s = "orange apple grapes pear".split()
>>> '/'.join(''.join(k) for k in [[s[j] for j in range(len(s)) if 1<<j&i] for i in range(1<<len(s))] if len(k)>1)
'orangeapple/orangegrapes/applegrapes/orangeapplegrapes/orangepear/applepear/orangeapplepear/grapespear/orangegrapespear/applegrapespear/orangeapplegrapespear'
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