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Using the `is` operator with Generics in C#

开发者 https://www.devze.com 2022-12-21 04:04 出处:网络
I want to do something like this:开发者_Python百科 class SomeClass<T> { SomeClass() { bool IsInterface = T is ISomeInterface;

I want to do something like this:

开发者_Python百科
class SomeClass<T>
{
   SomeClass()
   {
        bool IsInterface = T is ISomeInterface;
   }
}

What is the best way for something like this?

Note: I am not looking to constrain T with a where, but I would like my code to be aware of what types of interfaces T implements. I would prefer that I don't have to construct a T.


I don't think you can use the is operator for this. But you can use IsAssignableFrom:

bool IsInterface = typeof(ISomeInterface).IsAssignableFrom(typeof(T));


should use following instead

 bool IsInterface = typeof(ISomeInterface).IsAssignableFrom(typeof(T));

is operator

is operator is used to check whether the run-time type of an object is compatible with a given type.

An expression where the use of is conforms to the syntax, evaluates to true, if both of the following conditions are met:

  • expression is not null.
  • expression can be cast to type. That is, a cast expression of the form (type)(expression) will complete without throwing an exception. For more information, see 7.6.6 Cast expressions.

References

  • Does a Type Implement an Interface?
  • is operator


You can use IsAssignableFrom:

  class SomeClass<T>
  {
     SomeClass()
     {
        bool IsIComparable = typeof(IComparable).IsAssignableFrom(typeof(T));
     }
  } 


bool IsInterface = typeof(ISomeInterface).IsAssignableFrom(typeof(T))


I believe the best you can do it:

bool IsInterface = typeof(ISomeInterface).IsAssignableFrom(typeof(T));


You could try doing something like

Type Ttype = typeof(T);

That will give you the full power of the Type class, which has functions like "FindInterfaces".

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