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Counting number of children in hierarchical SQL data

开发者 https://www.devze.com 2022-12-21 03:23 出处:网络
for a simple data structure such as so: IDparentIDTextPrice 1Root 21Flowers 31Electro 42Rose10 52Violet5 64Red Rose12

for a simple data structure such as so:

ID    parentID    Text        Price
1                 Root
2     1           Flowers
3     1           Electro
4     2           Rose        10
5     2           Violet      5
6     4           Red Rose    12
7     3           Television  100
8     3           Radio       70
9     8           Webradio    90

For reference, the hierarchy tree looks like this:

ID    Text        Price
1     Root
|2    Flowers
|-4   Rose        10
| |-6 Red Rose    12
|-5   Violet      5
|3    Electro
|-7   Television  100
|-8   Radio       70
  |-9 Webradio    90

I'd like to count the number of children per level. So I would get a new column "NoOfChildren" like so:

ID    parentID    Text        Price  NoOfChildren
1                 Root               8
2     1           Flowers            3
3     1           Electro            3
4     2           Rose        10     1
5     2           Violet      5      0
6     4           Red Rose    12     0
7     3           Television  100    0
8     3           Radio       70     1
9     8           Webradio    90开发者_JAVA技巧     0

I read a few things about hierarchical data, but I somehow get stuck on the multiple inner joins on the parentIDs. Maybe someone could help me out here.


Using a CTE would get you what you want.

  • Recursively go through all children, remembering the root.
  • COUNT the items for each root.
  • JOIN these again with your original table to produce the results.

Test Data

DECLARE @Data TABLE (
  ID INTEGER PRIMARY KEY
  , ParentID INTEGER
  , Text VARCHAR(32)
  , Price INTEGER
)

INSERT INTO @Data
  SELECT 1, Null, 'Root', NULL
  UNION ALL SELECT 2, 1, 'Flowers', NULL
  UNION ALL SELECT 3, 1, 'Electro', NULL
  UNION ALL SELECT 4, 2, 'Rose', 10
  UNION ALL SELECT 5, 2, 'Violet', 5
  UNION ALL SELECT 6, 4, 'Red Rose', 12
  UNION ALL SELECT 7, 3, 'Television', 100
  UNION ALL SELECT 8, 3, 'Radio', 70
  UNION ALL SELECT 9, 8, 'Webradio', 90

SQL Statement

;WITH ChildrenCTE AS (
  SELECT  RootID = ID, ID
  FROM    @Data
  UNION ALL
  SELECT  cte.RootID, d.ID
  FROM    ChildrenCTE cte
          INNER JOIN @Data d ON d.ParentID = cte.ID
)
SELECT  d.ID, d.ParentID, d.Text, d.Price, cnt.Children
FROM    @Data d
        INNER JOIN (
          SELECT  ID = RootID, Children = COUNT(*) - 1
          FROM    ChildrenCTE
          GROUP BY RootID
        ) cnt ON cnt.ID = d.ID


Consider using a modified preorder tree traversal way of storing the hierarchical data. See http://www.sitepoint.com/hierarchical-data-database/

Determining number of children for any node then becomes a simple:

SELECT (right-left-1) / 2 AS num_children FROM ...
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