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Default value in a function in Python [duplicate]

开发者 https://www.devze.com 2022-12-21 02:19 出处:网络
This question already has answers here: "Least Astonishment" and the Mutable Default Argument
This question already has answers here: "Least Astonishment" and the Mutable Default Argument (32 answers) Closed 5 years ago.

I am noticing the following:

class c:
  def __init__(self, data=[]):
    self._data=data
a=c()
b=c()
a._data.append(1)
print b._data
[1]

Is this the correct behavior开发者_开发百科?


Yes, it's correct behavior.

However, from your question, it appears that it's not what you expected.

If you want it to match your expectations, be aware of the following:

Rule 1. Do not use mutable objects as default values.

def anyFunction( arg=[] ):

Will not create a fresh list object. The default list object for arg will be shared all over the place.

Similarly

def anyFunction( arg={} ):

will not create a fresh dict object. This default dict will be shared.

class MyClass( object ):
    def __init__( self, arg= None ):
        self.myList= [] if arg is None else arg 

That's a common way to provide a default argument value that is a fresh, empty list object.


This is a classic pitfall. See http://zephyrfalcon.org/labs/python_pitfalls.html, section 5: "Mutable default arguments"


Always make functions like this then:

def __init__ ( self, data = None ):
    if data is None:
       data = []

    self._data = data

Alternatively you could also use data = data or [], but that prevents the user from passing empty parameters ('', 0, False etc.).

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