I have a function specification that states it that should evaluate a polynomial function of one variable. The coefficient of the function is given as a list. It also accepts the value of the variable as a real.
For example: eval(2, [4, 3, 2, 1]) = 26 (1*x^3 + 2*x^2 + 3*x^1 + 4*x^0, where x = 2)
Here's the function in python, but I'm not sure 开发者_JAVA百科how to convert it to SML. I'm having trouble finding a way to pass it the iteration value without changing the parameters of the function. It needs to remain a real * real list -> real function.
def eval(r, L):
sum = 0
for i in range(0, len(L)):
sum = sum + L[i] * (r ** i)
return sum
The usual way to express sums in functional languages is a fold. You can get rid of the need for an index (and a function to raise an int to the power of another int) by multiplying the sum with r in each iteration:
fun eval radix lst = let
fun f (element, sum) = sum * radix + element
in
foldr f 0 lst
end
Now the function can be used like this:
- eval 10 [1,2,3];
val it = 321 : int
You can use explicit recursion to walk through the list of coefficients, exponentiate the radix, and sum up the total.
fun eval r =
let fun step (power, sum) (coeff :: rest) =
step (power * r, sum + coeff * power) rest
| step (_, sum) nil = sum
in step (1, 0)
end
Structurally, this is exactly like a fold, and it becomes clearer if we replace it with one.
fun eval r lst =
let fun step (coeff, (power, sum)) = (power * r, sum + coeff * power)
val (_, sum) = foldl step (1, 0) lst
in sum
end
You can reverse the order of operations to use Horner's scheme, as mentioned in KennyTM's comment: that would result in sepp2k's answer, which requires half as many multiplications, but uses more stack space.
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