How do you match something surrounded by 'foo' and 'bar' without matching foo and bar?

as opp开发者_如何学Pythonosed to regex:'foo.+bar'

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Use a group:

foo(.+?)bar

Then you will be able to refer to the group as $1 or \1, depending on the language and what you are doing with it.

As always, let me recommend Regular-Expressions.info for learning all about regexes.

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An alternative would be to use lookaround if the regex flavor you're using (which you didn't specify) supports it. .NET, Python do, Ruby and JavaScript don't (fully), for example:

(?<=foo).+(?=bar)

matches any number of characters if they are preceded by foo and followed by bar.

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Just use:

/foo(.+)bar/

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You can use:

foo(.+?)bar

or

foo(.*?)bar

The 2nd one will work even when there is nothing between foo and bar