I have a 114 row by 16 column data frame where the rows are individuals, and the columns are either their names or NA. For example, the first 3 rows looks like this:
name name.1 name.2 name.3 name.4 name.5 name.6 name.7 name.8 name.9 name.10 nam开发者_如何学Ce.11 name.12 name.13 name.14 name.15
1 <NA> <NA> <NA> <NA> <NA> <NA> <NA> <NA> <NA> <NA> Aanestad <NA> Aanestad <NA> Aanestad <NA>
2 <NA> <NA> <NA> <NA> <NA> <NA> <NA> <NA> Ackerman <NA> Ackerman <NA> Ackerman <NA> Ackerman <NA>
3 <NA> <NA> <NA> <NA> <NA> <NA> Alarcon <NA> Alarcon <NA> Alarcon <NA> Alarcon <NA> <NA> <NA>
I want to generate a list (if multiple unique names per row) or vector (if only one unique name per row) of all the unique names, with length 114.
When I try apply(x,1,unique)
I get a 2xNcol array where sometimes the first row cell is NA and sometimes the second row cell is NA.
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9]
[1,] NA NA NA NA "Alquist" NA "Ayala" NA NA
[2,] "Aanestad" "Ackerman" "Alarcon" "Alpert" NA "Ashburn" NA "Baca" "Battin"
When what I'd like is just:
Aanestad
Ackerman
Alarcon
...
I can't seem to figure out how to apply unique() while ignoring NA. na.rm, na.omit etc don't seem to work. I feel like I'm missing something real simple ...
Thanks!
unique
does not appear to have an na.rm
argument, but you can remove the missing values yourself before calling it:
A <- matrix(c(NA,"A","A",
"B", NA, NA,
NA, NA, "C"), nr=3, byrow=TRUE)
apply(A, 1, function(x)unique(x[!is.na(x)]))
gives
[1] "A" "B" "C"
You were very, very close in your initial solution. But as Aniko remarked, you have to remove NA
values before you can use unique.
An example where we first create a similar data.frame
and then use apply()
as you did -- but with an additional anonymous function that is used to combine na.omit()
and unique()
:
R> DF <- t(data.frame(foo=sample(c(NA, "Foo"), 5, TRUE),
bar=sample(c(NA, "Bar"), 5, TRUE)))
R> DF
[,1] [,2] [,3] [,4] [,5]
foo "Foo" NA "Foo" "Foo" "Foo"
bar NA NA NA "Bar" "Bar"
R> apply(DF, 1, function(x) unique(na.omit(x)))
foo bar
"Foo" "Bar"
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