Binary addition of 2 values represented as strings

I have two strings:

string a = "00001"; /* which is decimal 1 I've converted with next string:
string a = Convert.ToString(2, 2).PadLeft(5, '0'); */
string b = "00010";

I want to 开发者_如何学Goperform binary addition between the two so the answer will be 00011 ( 3).

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System.Convert should be able to do the work for you

int number_one = Convert.ToInt32(a, 2);
int number_two = Convert.ToInt32(b, 2);

return Convert.ToString(number_one + number_two, 2);

(you may have to tune the strings a bit)

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You do it just as you would do it on paper. Start from right and move left. if A[i] + B[i] + carry >= 2, carry remains 1 and you move on. Otherwise, write A[i] + B[i] + carry and set carry to 0.

a = "00001"; b = "00010";

carry = 0; a[4] + b[4] + carry = 1, write 1, set carry = 0: 00001

a[3] + b[3] + carry = 1, write 1, set carry = 0: 00011

And so on.

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private static bool[] BinaryAdd(bool[] originalbits, long valuetoadd)
    {
        bool[] returnbits = new bool[originalbits.Length];

        for (long i = 0; i <= valuetoadd - 1; i++)
        {
            bool r = false; //r=0
            for (long j=originalbits.Length-1;j<=originalbits.Length;j--)
            {
                bool breakcond = false;
                bool o1 = originalbits[j];
                if (r == false)
                {
                    if (o1 == false) { o1 = true; breakcond = true; }//break
                    else if (o1 == true) { o1 = false; r = true; }
                }
                else
                {
                    if (o1 == false) { o1 = true; breakcond = true; }//break
                    else if (o1 == true) { o1 = false; r = true; }
                }

                originalbits[j] = o1;
                if (breakcond == true)
                {
                    break;
                }
            }

        }
        returnbits = originalbits;

        return returnbits;
    }

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public static string AddBinary(string a, string b)
    {
        string result = "";
         
        int s = 0;
         
        int i = a.Length - 1, j = b.Length - 1;
        while (i >= 0 || j >= 0 || s == 1)
        { 
            s += ((i >= 0) ? a[i] - '0' : 0);
            s += ((j >= 0) ? b[j] - '0' : 0);
            result = (char)(s % 2 + '0') + result;

            s /= 2;
            i--; j--;
        }
        return result;
    }

Just it. Extra Link.

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I would recommend parsing the data to ints and then adding them, then outputing the result as binary.

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Very easy -- write a lookup table for 'addition' of binary characters, don't forget to carry if necessary, and send me 50% of the credit you get for the work.

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var sum = Convert.ToString(Convert.ToInt32("00010", 2) + Convert.ToInt32("00001", 2), 2).PadLeft(5, '0');

"00011"

PadLeft is not really needed, but if the strings had different length you would get a the same format. Example:

var sum = Convert.ToString(Convert.ToInt32("0000010", 2) + Convert.ToInt32("001", 2), 2).PadLeft(5, '0');

"00011"