i have following code:
SELECT *
FROM table
WHERE thread = $thread
AND (user != $user1 OR user != $user2)
i开发者_JS百科 want the code to pick all rows that contains $thread BUT the user isn't $user1 or $user2.
is my code correct? or should it be like:
SELECT *
FROM table
WHERE thread = $thread
(AND user != $user1 OR user != $user2)
thanks in advance
Use:
SELECT t.*
FROM TABLE t
WHERE t.thread = mysql_real_escape_string($thread)
AND t.user NOT IN (mysql_real_escape_string($user1), mysql_real_escape_string($user2))
Please use mysql_real_escape_string, or risk SQL injection attacks.
SELECT *
FROM table
WHERE thread = $thread
AND user != $user1
AND user != $user2
Use this:
SELECT *
FROM table
WHERE thread = $thread
(AND user != $user1 AND user != $user2)
Because you don't want if the user is either of user1 or user2, for this reason using 'AND' will be proper option here.
Also if the $thread
is not an integer field, you need enclose it in quotes eg:
WHERE thread = '$thread'
You could also use
SELECT *
FROM table
WHERE thread = '$thread'
AND user NOT IN ($user1, $user2)
Don't know which executes faster, but this is my preferred way because I like it's readability better.
I think you should also be using <> instead of !=
So:
SELECT *
FROM table
WHERE thread = $thread
AND user <> $user1
AND user <> $user2
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