I have a function that gets a class passed to it as a parameter. I would like to get the class name of the passed class as a string.
I tried putting this method in the passed class:
function getClassName()
{
return __CLASS__;
}
but if the class is开发者_运维问答 extended I assumed this would return the name of the subclass but it still returns the name of the super class which I find kind of odd.
So given a $var passed to a function as a parameter, is there a way to get a string of the class name?
Thanks!!
See get_class, that should be exactly what you're trying to achieve.
$class_name = get_class($object);
Simplest way how to get Class name without namespace is:
$class = explode('\\', get_called_class());
echo end($class);
Or with preg_replace
echo preg_replace('/.*([\w]+)$/U', '$1', get_called_class());
__ CLASS __ with return the name of the class the method is implemented in.
If you want to get the class name of an object passed then you can use:
get_class($param);
Also, if you're using PHP5 then the Reflection classes provided are also useful.
Use get_class:
$className = get_class($object);
Straight from the php docs: http://uk.php.net/manual/en/function.get-class.php
<?php
abstract class bar {
public function __construct()
{
var_dump(get_class($this));
var_dump(get_class());
}
}
class foo extends bar {
}
new foo;
?>
The above example will output:
string(3) "foo"
string(3) "bar"
you could also add a method into the passed class(es) returning this:
var_dump(get_called_class());
精彩评论