Print database data in html Table

I know how to print data from database on html table but i have one task that i can not understand开发者_如何学运维, and i can not do it. I have a table in database and when i select those data i want them to display on html table but something like this:

Image http://img683.imageshack.us/img683/9350/tablea.png

---

To achieve a table layout like that you just need to condition the placement of the end of your table rows.

<table>
  <tr>
<?php
  $count = 0;
  while($row = mysql_fetch_assoc($result)) :
    $count++;
?>
    <td><?php echo $row['value'] ?></td>
<?php if($count % 2 == 0 || $count == mysql_num_rows($res)) : ?>
  </tr>
<?php if($count != mysql_num_rows($result)) : ?>
  <tr>
<?php endif; ?>
<?php endif; ?>
<?php endwhile; ?>
</table>

What the above does is use the modulus operator (%, calculates the remainder from division) to print a closing and opening row tag whenever we're at an evenly numbered result.

Also, if you wanted to change your table layout to be 3 or 4 columns wide all you need to do is change the number applied to the modulus:

$count % 3 == 0 //3 columns
$count % 4 == 0 //4 columns, etc

---

<table>
    <?php while (TRUE) { ?>
        <?php
            // Make an array of n rows. Trailing items may be FALSE if there
            // are not enough rows to fill the table row.
            //
            $rows= array();
            for ($i= 0; $i<n; $i++)
                $rows[$i]= mysql_fetch_assoc($result);
            if (!$row[0])
                break;
        ?>
        <tr>
            <?php foreach ($rows as $row) { ?>
                <td>
                    <?php if ($row) { ?>
                        Value: <?php echo(htmlspecialchars($row['value']); ?>
                    <?php } ?>
                </td>
            <?php } ?>
        </tr>
    <?php } ?>
</table>