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PySVN error: URL doesn't exist

开发者 https://www.devze.com 2022-12-19 16:51 出处:网络
I got a SVN repository copied onto my computer using svnsync. Now when I开发者_StackOverflow中文版 try to replay it using PySVN it fails at a specific revision (29762) with the message:

I got a SVN repository copied onto my computer using svnsync. Now when I开发者_StackOverflow中文版 try to replay it using PySVN it fails at a specific revision (29762) with the message:

pysvn._pysvn_2_6.ClientError: URL 'svn://svn.zope.org/repos/main/ZODB/trunk/src/Persistence' doesn't exist

I can checkout or update until the previous revision (29761) ok but after that I get this error.

My objective is to analyze the code structure and it's evolution so I have

client.update(path,
revision=pysvn.Revision(pysvn.opt_revision_kind.number,
RevNumber),ignore_externals=False)

within a for loop that increments RevNumber

I am ok with ignoring this specific revision, so if there is a way around it that will allow my checked-out code to progress and be analyzed, that will be fine (as long as there aren't many more instances of this happening).

Nevertheless, if my repo is a copy of a working repo, why doesn't it work and how does the original one function properly?


Although the error message doesn't hint to that, I believe it was caused by running out of disk space. After deleting other files on the drive and re-running the script it worked fine.


try:
    client.update(path,revision=pysvn.Revision(pysvn.opt_revision_kind.number,RevNumber),ignore_externals=False)
except: 
    print "Revision skipped at", RevNumber
    continue

This does not solve the problem, but you can use try/ except for your code to go on, if you are ok with omitting some revisions, like you've said.

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