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How to get rid of extra elements in string literal in php?

开发者 https://www.devze.com 2022-12-19 13:57 出处:网络
I have number like 9843324+ and now I want to get rid of + at the end and only have 9843324 and so how should I do this in php ?

I have number like 9843324+ and now I want to get rid of + at the end and only have 9843324 and so how should I do this in php ?

Right now I am doing $customer_id = explode('+',$o_household->getInternalId); also $o_household->getInternalId returns me 9843324+ but I want 9843324, how can 开发者_Go百科I achieve this ?

Thanks.


if you just want to pop the + off the end, use substr.

$customer_id = substr($o_household->getInternalId, 0, -1);

or rtrim

$customer_id = rtrim($o_household->getInternalId, "+");


You can use a regeular expression to remove anything that isn't a number

$newstr = preg_replace("/[^0-9]+/","",$str);


$customer_id = rtrim ( $o_household->getInternalId, '+' );

rtrim function reference

rtrim removes the characters in the second argument (+ only in this case) from the end of a string.

In case there is no + at the end of the string, this won't mess up your value like substr.

This solution is obviously more readable and faster than, let's say preg_replace too.


you could use intval($o_household->getInternalId)


Is there a reason you need to use explode? i would just use substr as Andy suggest or str_replace. Either would work for the example you provided.


You can use intval to get the integer value of a variable, if possible:

echo intval($str);

Be aware that intval will return 0 on failure.

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