I am getting this error when I call my method dismissView. Here is the method stub:
-(IBAction)dismissView
{
RootViewController *rootController = [[RootViewController alloc] initWithNibName:@"RootViewController" bundle:nil];
[self.navigationController popToViewController:rootController animated:YES];
}
That should work, and I've checked, rootControlle开发者_如何学Cr is initialized and allocated. Any ideas?
I had this problem recently and solved with something like this...
[self.navigationController popToViewController:[self.navigationController.viewControllers objectAtIndex:1] animated:YES];
The -popToViewController
is used to pop view controllers OFF the stack, down to one that already exists. Your UINavigationController
has a stack of ViewControllers (stored in the viewControllers
property), when you popToViewController
, you're going to want to pass one of the elements in that array as the first argument.
What you most likely want to do in this case is use -popViewControllerAnimated:
, which will remove the top ViewController
from the stack
Swift 4
For anyone still looking for a better solution that doesn't involve the UINavigationController stack indexes, which is getting more problematic with bigger navigation stack - here's the easiest way to solve this:
if let destinationViewController = navigationController?.viewControllers
.filter(
{$0 is DestinationViewController})
.first {
navigationController?.popToViewController(destinationViewController, animated: true)
}
You're allocating the RootViewController right there. It does not exist in the navigation controller's stack, so no matter how far you pop, you won't reach it.
If you are using Storyboads, use this segue:
#import "PopToControllerSegue.h"
@implementation PopToControllerSegue
- (void) perform
{
UIViewController *sourceViewController = (UIViewController *)self.sourceViewController;
UIViewController *destinationViewController = (UIViewController *)self.destinationViewController;
for (UIViewController* controller in sourceViewController.navigationController.viewControllers) {
if ([controller isKindOfClass:destinationViewController.class]) {
[sourceViewController.navigationController popToViewController:controller animated:YES];
return;
}
}
NSLog(@"PopToControllerSegue has failed!");
}
@end
When using Push Segues you can easily go back to the root using this method:
[self.navigationController popToRootViewControllerAnimated:YES];
When using Modal Segues (because of the word dismiss in the question and as a general reference) you can dismiss
the view controller using this method:
[self dismissViewControllerAnimated:YES completion:nil];
The UINavigationController
has a stack of ViewControllers
which is stored in the viewControllers(NSArray) property. Enumerate to the required ViewController
and pop to that ViewController
.
Following code should solve the problem.
-(IBAction)dismissView
{
NSArray *array = self.navigationController.viewControllers;
for (id controller in array) {
if ([controller isKindOfClass:[RootViewController class]]) {
[self.navigationController popToViewController:controller animated:YES];
}
}
}
Try this one line solution.
Swift 4+:
self.navigationController?.popToViewController ((self.navigationController?.viewControllers[1]) as! Your_ViewController, animated: true)
Objective-C:
[self.navigationController popToViewController:[self.navigationController.viewControllers objectAtIndex:1] animated:YES];
In my case the problem was that I was in the root ViewController and this works only for VCs that are stacked over it. To pop to the RootViewController use
navigationController?.popToRootViewController(animated: true)
self.navigationController?.present(viewControllers, animated: true, completion: nil)
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