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Opening the user's home folder?

开发者 https://www.devze.com 2022-12-19 05:28 出处:网络
My XULRunner application has a button named \"Show Recordings\". Pressing it should result in Windows Explorer opening the folder for the user. How can I achieve this?

My XULRunner application has a button named "Show Recordings". Pressing it should result in Windows Explorer opening the folder for the user. How can I achieve this?

I can't find it 开发者_JAVA技巧in the File I/O documentation, perhaps I'm looking in the wrong place.

Edit The problem is not finding the path, but telling the system to open the folder. I can't seem to find a "openFolder" function.


You're looking for the reveal() method on nsILocalFile.


Do you mean:

  %HOMEPATH%

And by that I mean, if you want a global variable to get the current user's home directory path, use %HOMEPATH%. I guess you have to set that button to this value. For a list of Windows environment variables, start at the wiki article.

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