Can you make an assig开发者_JAVA百科nment on conditional statement in php as so:
if(siteName_err = isValid("sitename", $_POST['sitename'], false))
{
$siteName = $_POST['sitename'];
}
Yes.
I think the most common use scenario for this is when using MySQL. For example:
$result = mysql_query("SELECT username FROM user");
while ($user = mysql_fetch_assoc($result)) {
echo $user['username'] . "\n";
}
This works because $user
is the result from the assignment. Meaning, whatever is stored in your assignment, is then used as the conditional. In other words,
var_dump($i = 5);
// is equivalent to
$i = 5;
var_dump($i);
Both will print int(5)
, obviously.
Yes.
Honestly, why don't you try it out? Languages where you're not allowed to do this sort of thing usually generate compiler/parser errors.
PHP takes most of its basic syntactic elements from C, which includes that every assignment returns a value. Therefore this is valid.
Yah, you can do that.
If you're asking because you tried it and got a crazy error, try making siteName_err
a valid variable name by putting a dollar sign $
before it.
Yes sure and you can do also the same for while constructs
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