Can Django ORM do an ORDER BY on a specific value of a column?

I have a table 'tickets' with the following columns

• id - primary key - auto increment
• title - varchar(256)
• status - smallint(6) - Can have any value between 1 and 5, handled by Django

When I'll do a SELECT * I want the rows with status = 4 at the top, the other records will follow them. It can be achieved by the following query:

select * from tickets order by status=4 DESC

Can this query be ex开发者_如何学Goecuted through Django ORM? What parameters should be passed to the QuerySet.order_by() method?

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q = Ticket.objects.extra(select={'is_top': "status = 4"})
q = q.extra(order_by = ['-is_top'])

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I did this while using PostgresSql with django.

from django.db.models import Case, Count, When

Ticket.objects.annotate(
    relevancy=Count(Case(When(status=4, then=1)))
).order_by('-relevancy')

It will return all objects from Ticket, but tickets with status = 4 will be at the beginning.

Hope someone will find it useful.

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For those in need just like me that stumbled on this now and are using newer versions of Django

from django.db.models import Case, When

Ticket.objects.annotate(
    relevancy=Case(
        When(status=4, then=1),
        When(status=3, then=2),
        When(status=2, then=3), 
        output_field=IntegerField()
    )
).order_by('-relevancy')

Using Count() will return 1 or 0 depending if your case was found or not. Not ideal if ordering by a couple of status