I have a local directory with executable in it (e.g. foo_dir/bin/bar). I typed "foo", but foo_dir wasn't suggested. What cames out is other program in $PATH (such as bootlogd).
How should I开发者_JS百科 config my zshrc? Thanks
I think adding "." to your $PATH variable will fix this issue. By default $PATH contains standard bin directory i.e /usr/bin, /bin, /usr/local/bin.
I found a workable solution, by "setopt autocd", but the side effect is when executing some directory, you'll cd into it.
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