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How to show a MFC dialog without stealing focus on the other window

开发者 https://www.devze.com 2022-12-18 08:19 出处:网络
I have the dialog shown with ShowWindow(hWnd, SW_SHOWNOACTIVATE); But it doesn\'t work, the new dialog still steals the focus, why is it?

I have the dialog shown with ShowWindow(hWnd, SW_SHOWNOACTIVATE); But it doesn't work, the new dialog still steals the focus, why is it?

here is the some code snippets from my program, Q开发者_Go百科ueryWindow is the MFC dialog class linked with the dialog:

QueryWindow window;
//window.DoModal();
window.Create(QueryWindow::IDD);
window.ShowWindow(SW_SHOWNOACTIVATE);


There are few ways to skip dialog from getting focused:

  • Make you OnInitDialog() to return zero value. Example:

    BOOL QueryWindow::OnInitDialog()
    {
        CDialog::OnInitDialog();
    
        return FALSE; // return 0 to tell MFC not to activate dialog window
    }
    

    This is the best and most correct solution.

  • Add WS_EX_NOACTIVATE style to your dialog window. You can edit dialog resource properties or change it in runtime:

    BOOL QueryWindow::PreCreateWindow(CREATESTRUCT& cs)
    {
        cs.dwExStyle |= WS_EX_NOACTIVATE;
    
        return CDialog::PreCreateWindow(cs);
    }
    

    Side-effect: you can use controls on your window, but it will look like it was not activated.

  • Last way is to save foreground window before creating your dialog and set foreground window at the end:

    BOOL QueryWindow::Create(LPCTSTR lpszTemplateName, CWnd* pParentWnd)
    {
        CWnd* pForeground = GetForegroundWindow();
    
        const BOOL bRes = CAlertDialog::Create(lpszTemplateName, pParentWnd);
    
        if(pForeground)
            pForeground->SetForegroundWindow();
        return bRes;
    }
    

    This is the worth solution because potentially you can get flicker.

Important!

Don't forget to control following API calls:

  • ShowWindow - you can use SW_SHOWNOACTIVATE, but can't use SW_SHOW
  • SetWindowPos - add flag SWP_NOACTIVATE
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