I'm currently reading an article , but I do not really understand how this work with the logical operator. Can anyone explain this to me?
eg. If I want to have 4 level securities开发者_JS百科 with customer, employee, supervisor and Admin.
[Serializable]
[Flags]
public enum WebRoles
{
customer= 1 << 0,
employee= 1 << 1,
supervisor = 1 << 2,
Admin = 2 << 3
}
and then how I should implement the following logic.
if (Roles != 0 && ((Roles & role) != role))
return false;
Can anyone provide me some knowledge of this implementation?
Thank you very much.
Daoming
They're using an enum
as a bit map: if a specific bit is set, so you have that privilege. They're also using a left shift operator. Let me try to demonstrate all that at once:
Role Decimal Binary Shifted Decimal -------- ------- ------ ------- ------- Customer = 1 = 000001 = 000001 = 1 Employee = 1 = 000001 = 000010 = 2 Supervisor = 1 = 000001 = 000100 = 4 Admin = 2 = 000010 = 010000 = 16
This way you can combine two roles. For instance, some user can play Employee
and Supervisor
at same time, just having correspondent bits set.
And how to check if a bit is set? It's exactly what that (Roles & role) != role)
do. For example:
WebRoles user = WebRoles.Employee | WebRoles.Supervisor;
bool isEmployee = (user & WebRoles.Employee) == WebRoles.Employee; // true
If you test user variable to check if that Employee
bit is set, that &
operator will return all match bits.
Hope this help; feel free to edit this answer
This example uses the bitwise shift operator: "<<". This operator takes the bits and shifts them. For example, "1 << 3" results in the number 8. So, in binary,
customer = 0001
employee = 0010
supervisor = 0100
admin = 1000 (I think this was supposed to read 1 << 3)
Now, you can assign people multiple roles using the bitwise-or operator. This would be a single vertical-bar "|". The bitwise or combines the two numbers bit-by-bit, setting each bit that is set in either of the two operands.
myRole = customer | employee = 0011
The if-statement you have is intended to tell whether someone has a particular role. It uses bitwise-and: "&". Bitwise-and combines the two numbers, setting a bit only if the bit is set in both the operands.
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