How can I replace ALL instances of a string in the previous command in Bash? [duplicate]

This question already has answers here: ^word^replacement^ on all matches in Bash? (6 answers) Closed last year.

If I have just entered the following command in Bash:

开发者_JS百科echo foo

I can change foo to bar by typing:

^foo^bar

Which results in the following command being executed:

echo bar

Now if I enter:

echo foo foo

Is there a way to change both instances of foo to bar just by using the caret (^) operator?

Additionally, are there man pages for shell operators like ^? man ^ results in "No manual entry for ^".

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That particular feature is called quick substitution; its documentation can be found in the Event Designators section of the Bash Manual. You can't do what you want with quick substitution; you'll have to resort to something slightly more verbose:

!!:gs/foo/bar/

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Nor sure how to do it with caret substitution, but here's how you do it with history:

!!:gs/foo/bar/

Let me break that down:

!! - reruns the last command. You can also use !-2 to run two commands ago, !echo to run the last command that starts with echo

:gs says to do a global (all instances) search/replace. If you wanted to just do replace the first instance, you would use ':s'

Finally, /foo/bar/ says to replace foo with bar

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Try:

^foo^bar^:&

As you know ^foo^bar^ performs just one substitution, and the :& modifier repeats it.

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Caret substitution and other similar shortcuts are found in the Event Designators subsection of the HISTORY EXPANSION section of the bash(1) man page.

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If you're looking for something less difficult to memorize that accomplishes the same thing as the above !!:gs/foo/bar/, you could always create a function in your .bash_profile start-up script. I chose replace().

replace() {
    eval $(echo $(fc -ln -1) | eval "sed 's/${1}/${2}/g'") #compact form
}

OR, Less convolutedly

replace() {
    string=$(fc -ln -1) #gets last command string
    repcmmd="sed 's/${1}/${2}/g'" #build replacement sed command from fn input
    eval $(echo $string | eval $repcmmd) #evaluates the replacement command
}

Then the replace all can be made with

echo foo foo
replace foo bar

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^word^  ........... erase word
^word^^ ........... delete everything until the end of the line