Regex: Match this string

I can't figure this out:

22.584\r\n\t\t\tl-6.579-22

I want to match the "\r\n\t\开发者_如何学运维t\t" and replace with a single space " ". Problem is the number of "\t", "\r", and "\n" fluctuates, as do the surrounding characters.

Help!

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s/\s+/ /g

s/(?:\\[rnt])+/ /g

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In PHP:

preg_replace("/(?:\\\[trn])+/", " ", $str);

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sed 's/\\[rnt]/ /g;s/  */ /g'

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'22.584\r\n\t\t\tl-6.579-22'.gsub(/(\\[rnt])+/, ' ')

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#!/usr/bin/ruby1.8

s = "22.584\r\n\t\t\tl-6.579-22"
p s                           # => "22.584\r\n\t\t\tl-6.579-22"
p s.gsub(/[\r\n\t]+/, ' ')    # => "22.584 l-6.579-22"

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I'd treat the CR-NL as one atom:

str.gsub!(/(?:\r\n)+\t+/, ' ')