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Why do the instance variables of the object being passed in have to be accessed using the dot notation?

开发者 https://www.devze.com 2022-12-18 01:03 出处:网络
-(void) addFractions: (Fraction*) f { numerator = numerator * f.denominator + denominator *f.numerator; denominator = denominator *f.denominator;
-(void) addFractions: (Fraction*) f
{
    numerator = numerator * f.denominator
    + denominator *f.numerator;

    denominator = denominator *f.denominator;
}

//This is objective c-2.0

// this is the .h file for the .m above

-(void) addFractions : (Fraction*) f;

Don’t forget that you can refer to the Fraction that is开发者_StackOverflow中文版 the receiver of the message by its fields:numerator and denominator.On the other hand,you can’t directly refer to the instance variables of the argument fthat way.Instead,you have to obtain them by apply- ing the dot operator to f(or by sending an appropriate message to f)


In order to bring both fractions to use the same denominator.

I mean, a/b+c/d = ad/(bd) + cb/(db) = (ad + cb) / (b*d).


Imagine you have two fractions p/q and r/s that you'd like to add to a new fraction a/b. What does each line do?

// a = (p * s) + (q * r)
numerator = numerator * f.denominator + denominator * f.numerator;

// b = (r * s)
denominator = denominator *f.denominator;

Together you have:

 a    p * s + q * r
--- = -------------
 b        r * s

This is the traditional way to add two fractions with arbitrary, different denominators. Here's an example -- say you wanted to add 3/5 and 2/9:

 a    3 * 9 + 2 * 5   27 + 10   37
--- = ------------- = ------- = --
 b        5 * 9          45     45

Verifying, we see that this is indeed correct.


a.b (a dot b) is syntactic sugar for using the member variable accessors [a b], or mutators [a setb] when used as an lvalue.

I really don't understand what you are complaining about; this code is as clear And compact as any language is possible to be. That's how I would write it in pseudocode, too.

The rest is just maths.

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