Is there a way to combine two or more CSS selectors using a boolean condition - 开发者_如何学运维and
, or
, not
?
Consider this <div>
:
<div class="message error">
You have being logged out due too much activity.
</div>
Could I select only those elements that contain both the classes for instance?
Something along the lines of div.message && div.error
?
These should work:
&& = div.message.error {}
|| = div.message, div.error {}
Don't think you can do "not"
Edit: Just did a quick test to confirm:
<html>
<head>
<style type="text/css">
div.error.message {
background-color: red;
}
div.message, div.error {
border: 1px solid green;
}
</style>
</head>
<body>
<div>None</div>
<div class="error">Error</div>
<div class="message">Message</div>
<div class="error message">Error Message</div>
</body>
</html>
The "message", "error" and "error message" divs all have a green border and only the "error message" div has a red background.
Try div.message.error
.
This is a seriously old post, but I came across it and figured I'd add to it with the current CSS :not()
selector:
Select BOTH classes
.message.error {}
Select EITHER class
.message, .error {}
Select NEITHER class
div:not(.message):not(.error) {}
.message {
border: 1px solid;
}
.error {
color: red;
}
.message,
.error {
margin-bottom: 12px;
padding: 12px;
}
.message.error {
background: #ffcfcf;
}
div:not(.message):not(.error) {
font: normal 20px "Comic Sans MS", cursive, sans-serif;
}
<div class="message">
ONLY .message
</div>
<div class="error">
ONLY .error
</div>
<div class="message error">
BOTH classes
</div>
<div class="neither">
NEITHER class
</div>
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