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Populating columns of a window

开发者 https://www.devze.com 2022-12-17 22:54 出处:网络
What I am trying to do is populate two columns in a window.This columns will have the name of the global variable and the path it to it.I am having problems displaying what I need in the windows.

What I am trying to do is populate two columns in a window. This columns will have the name of the global variable and the path it to it. I am having problems displaying what I need in the windows.

        <TabItem Header="Global Variables" GotFocus="GlobalVariablesTab_GotFocus">
           <dc:TreeListView Name="tvwGlobalVariables"  dc:ColumnLayoutManager.Enabled="True" >
                <dc:TreeListView.Columns>

                    <!--First Column. -->
                   <dc:StdGridViewColumn Header="Variable" Width="200" >

                         <dc:StdGridViewColumn.CellTemplate>
                             <DataTemplate>
                                <TextBlock TextTrimming="CharacterEllipsis"/>
                            </DataTemplate>
                         </dc:StdGridViewColumn.CellTemplate>
                    </dc:StdGridViewColumn>

                    <!-- Second Column-->
                     <dc:StdGridViewColumn Header="Result" dc:ColumnRange.IsFillColumn="True"/>

               </dc:TreeListView.Columns> 
            </dc:TreeListView> 
        </TabItem>

This is the tab that has the area I need to populate. The first column for the name and the second will be for the path. I may be missing something as well.

    private void GlobalVariablesTab_GotFocus(object sender, RoutedEventArgs e)
    {
        lvGlobals.Items.Clear();
        sman = SchemaManager.SchemaManager.GetInstance();
        IEnumerator enumerator = sman.GetGlobalVariableEnumerator();
        while (enumerator.MoveNext()) 
        {
            DictionaryEntry entry = (DictionaryEntry) enumerator.Current;
            ListViewItem lvi = new ListViewItem();//new string[] {entry.Key.ToString(), entry.Value.ToString()});
            lvi.Tag = entry.Key.ToString() + en开发者_运维知识库try.Value.ToString();
        }
    }

Currently I have lvi holding both parts but I will need one part to go to the first column and the other part to the other column. I don't intend to keep lvi if I don't need it. Either way I need to get entry.key displayed in the first column and entry.value in the second. Any ideas?


I don't know what the SchemaManager is so I just used a Hashtable with some dummy data to get an enumerator with some dictionary entries. Below sample code uses a regular WPF listview with two columns with no formatting to keep it simple.

XAML:

<Window x:Class="TwoColsDemo.Window1"
    xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
    xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
    Height="300" Width="300">

    <ListView ItemsSource="{Binding Path=Data}">
        <ListView.View>
            <GridView>
                <GridView.Columns>
                    <GridViewColumn Header="Key" DisplayMemberBinding="{Binding Path=Key}" />
                    <GridViewColumn Header="Value" DisplayMemberBinding="{Binding Path=Value}" />
                </GridView.Columns>
            </GridView>
        </ListView.View>
    </ListView>
</Window>

Code behind:

using System.Collections;
using System.Collections.Generic;
using System.Windows;

namespace TwoColsDemo
{
    public partial class Window1 : Window
    {
        public Window1()
        {
            InitializeComponent();

            Hashtable sman = new Hashtable();
            sman.Add("Key1", "Value1");
            sman.Add("Key2", "Value2");

            Data = new List<DictionaryEntry>();

            IEnumerator enumerator = sman.GetEnumerator();
            while (enumerator.MoveNext())
            {
                DictionaryEntry entry = (DictionaryEntry)enumerator.Current;
                Data.Add(entry);
            }

            DataContext = this;
        }

        public List<DictionaryEntry> Data { get; private set; }
    }
}
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