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Regex Matching numbers with floating point

开发者 https://www.devze.com 2022-12-17 22:53 出处:网络
I have this pattern: [0-9]*\\.?[0-9] It matches numbers but it also matches 3.5.4 as: 3.5 .4 How to fix that(this input shouldn\'t be matched)?

I have this pattern:

[0-9]*\.?[0-9]

It matches numbers but it also matches 3.5.4 as:

  1. 3.5
  2. .4

How to fix that(this input shouldn't be matched)?

UPDATE:

this also should work on input: 1 3.5.4 10

1.2. is not allowed

.3 i开发者_如何学Gos allowed

any char that is not poart of numer is not allowed, like: a1 2.4f 3. 45, 67!


To match a json number:

^[-]?(0|[1-9][0-9]*)(\.[0-9]+)?([eE][+-]?[0-9]+)?$

Regex Matching numbers with floating point

Use this regex to match .123:

^[-]?((0|[1-9][0-9]*)(\.[0-9]+)?|\.[0-9]+)([eE][+-]?[0-9]+)?$


Updated answer after comment from poster:

Use lookahead / lookbehind to make sure that the characters before and after are spaces:

Here's a version that closely matches yours, but that won't make partial matches:

(?:^|(?<=\s))[0-9]*\.?[0-9](?=\s|$)

For both these examples, when run on the string 1 2.3.4 5.6 it matches only 1 and 5.6.


You have to decide if you want to accept numbers without leading zeros (eg .123). If you don't then the regex is easy:

^-?[0-9]+(\.[0-9]+)?$

If you do then it's a little more complex:

^-?(?:[0-9]+|[0-9]*\.[0-9]+)$

Both presume that a decimal point must be followed by at least one digit. If you don't accept negative numbers then the leading -? is unnecessary.


Your regex is not anchored. If you want to match lines that contain only numbers and nothing else use:

^[0-9]*\.?[0-9]$


You should not use a regex for this unless you really need to.

Instead, you should use your language's built-in number parsing methods.

I assume from your other questions that you're using Javascript; if so, you should call parseFloat.

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