I have looked at some of the related posts on this subject but i can't figure out how to solve my problem. I guess it has something to do with the fact that its monday.
Well, here goes. i have a XML object containing:
<root>
<page>
<text>
<style properties=""/>
<label> Text one</label>
</text>
<text>
<style properties=""/>
<label> Text two</label>
</text>
</page>
<page>
<text>
<style properties=""/>
<label> Text three</label>
</text>
<text>
<style properties=""/>
<label> Text four</label>
</text>
</page>
</root>
And i want to replace only the label node with a new one. i put the new ones in an XMLList but now im stuck at how im supose to replace the actual nodes. This is how the XMLList looks like:
<page>
<text>
<style properties=""/>
<label> Replace the first one</label>
</text>
<text>
<style properties=""/>
<label> Replace the second one</label>
</text>
</page>
<page>
<text>
开发者_如何转开发 <style properties=""/>
<label> Replace the third one</label>
</text>
<text>
<style properties=""/>
<label> Replace the fourth one</label>
</text>
</page>
A simple example:
// xml = your XML object
xml.page[0].text[0].label = 'new text';
xml.page[0].text[1].label = 'new text 2';
trace (xml.toXMLString());
returns:
<root>
<page>
<text>
<style properties=""/>
<label>new text</label>
</text>
<text>
<style properties=""/>
<label>new text 2</label>
</text>
</page>
<page>
<text>
<style properties=""/>
<label>Text three</label>
</text>
<text>
<style properties=""/>
<label>Text four</label>
</text>
</page>
</root>
You can use e4x to get the XMMList and then the parent function in a loop or doing what you want with the list:
var r:XML=<root>
<page>
<text>
<style properties=""/>
<label>new text</label>
</text>
<text>
<style properties=""/>
<label>new text 2</label>
</text>
</page>
<page>
<text>
<style properties=""/>
<label>Text three</label>
</text>
<text>
<style properties=""/>
<label>Text four</label>
</text>
</page>
</root>;
var xl:XMLList=r.page.text.label;
// use the first element of the list
xl[0].parent().label="i do what i want";
var i:int=0;
// or loop over each elment if the list
for each (var xml:XML in xl){
xml.parent().label=i + " : " + xml.toString();
i++;
}
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