i have this example code:
while ($row = mysql_fetch_object($result1)) {
echo '<input type="radio" name="vote" value='.开发者_如何学Go$row->avalue.'/> ';
echo '<label >'.$row->atitle.'</label><br>';
}
this displays 4 radio buttons alongwith their labels. now I am using the following jquery function to POST.
$("#submit_js").click(function() {
$.post(
"user_submit.php",
{//how to POST data?},
function(data){
});
});
I want to post the value associated with the radio button. but how do i select the value? how do i determine what radio button is selected and POST it?
$("[name='vote']:checked").val()
will get you the value of the selected radio button.
$("#submit_js").click(function() {
$.post(
"user_submit.php",
{vote: $("[name='vote']:checked").val()},
function(data){
});
});
Jquery serialize is the best way to do this kind of things: http://docs.jquery.com/Ajax/serialize
$("#submit_js").click(function() {
$.post(
"user_submit.php",
$("form").serialize(),
function(data){
});
});
If there is no radio button selected the radio button will not be added to the serialized string. In this case we can make a workaround by adding another one exactly like the following:
<input type="radio" name="vote" value="" checked style="display:none;">
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