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jQTouch Spinning Wheel (Cubiq) Implementation Won't Work

开发者 https://www.devze.com 2022-12-17 10:30 出处:网络
I am trying to get a nice Spinning Wheel working within my webapp. However, I keep receiving an error within Mobile Safari that the variable \'blabla\' cannot be found.

I am trying to get a nice Spinning Wheel working within my webapp.

However, I keep receiving an error within Mobile Safari that the variable 'blabla' cannot be found.

I have implemented both of these suggested solutions:

  1. Change SpinningWheelCSS
  2. Change JQTouch CSS, JS files, and add JQTouch wrapper to body

Neither worked for me.

I am trying to use the incredible Spinning Wheel by Cubiq.o开发者_运维知识库rg.

I'm likely doing something wrong, but for the life of me I can't figure out what it is. Help is very much appreciated.


I downloaded the very latest version of JQTouch from the trunk at Google Code: http://code.google.com/p/jqtouch/source/checkout

This fixed the problem, as the the latest version has included a namespace in the JQTouch.css stylesheet, which resolves the conflicts with the Spinning Wheel plugin.

Hopefully this helps someone else who is experiencing the same problem.


I am using the spinning wheel in my web app and I removed the cancel/done buttons since I call a new #id for it, you just need to edit the js and css coming along with the spinningwheel. However, no previous/next buttons are visible there, do you mean the cancel/done ones?

I call the wheel on a page where I also have a radio group and it won't function when the wheel's there - do you have a clue what I'm doing wrong? I also have a picture on that screen, if the user clicks it, it should change. As long as the wheel does not appear, it all goes well...


Your href where you call the class should direct to a #htmlid tag on the same page

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