I would like to extract certain rows from a log file using native Windows command line tools or batch file (.bat). Here's a sample log file:
2009-12-07 14:32:38,669 INFO Sample log
2009-12开发者_Python百科-07 14:32:43,029 INFO Sample log
2009-12-07 14:32:45,841 DEBUG Sample log
2009-12-07 14:32:45,841 DEBUG Sample log
2009-12-07 14:32:52,029 WARN Sample log
2009-12-07 14:32:52,466 INFO Sample log
How to extract and print lines which have tag "WARN"? How to do this with PowerShell?
One way:
findstr WARN log.txt
More complex:
for /f "tokens=1,2,3,4* delims=, " %i in (log.txt) do @if "%l"=="WARN" echo %i %j %m
OUTPUT:
2009-12-07 14:32:52 Sample log
you can do it with PowerShell using select-stirng :
select-String WARN *.log
If PowerShell (as suggested by Alon) isn't an option, maybe Logparser will fulfill for your needs: http://www.microsoft.com/downloads/details.aspx?FamilyID=890cd06b-abf8-4c25-91b2-f8d975cf8c07&displaylang=en
there are several ways, findstr/find like what others show you. Or you can use vbscript
Set objFS=CreateObject("Scripting.FileSystemObject")
Set objArgs = WScript.Arguments
strFile= objArgs(0)
Set objFile = objFS.OpenTextFile(strFile)
Do Until objFile.AtEndOfStream
strLine = objFile.ReadLine
If InStr(strLine,"WARN") > 0 Then
WScript.Echo strLine
End If
Loop
save as mygrep_warn.vbs and on command line
c:\test> cscript //nologo mygrep_warn.vbs myfile.log
Other methods, if you can download stuff and use GNU *nix tools ported to win32
C:\test>grep -i "warn" file
2009-12-07 14:32:52,029 WARN Sample log
C:\test>gawk "BEGIN{IGNORECASE=1}/warn/" file
2009-12-07 14:32:52,029 WARN Sample log
Get-EventLog -LogName application -EntryType warning
and export the output as you like
You can always try the original DOS "find" command, it's pretty crappy though:
c:>find " WARN " filename.log
---------- FILENAME.LOG
2009-12-07 14:32:52,029 WARN Sample log
c:>
You can't use wildcards in the filename either.
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