<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:param name="pXml1" select="''" />
<xsl:param name="pXml2" select="''" />
<xsl:param name="pRoot" sele开发者_如何学Goct="'root'" />
<xsl:template match="/">
<xsl:variable name="vXml1" select="document($pXml1)" />
<xsl:variable name="vXml2" select="document($pXml2)" />
<xsl:element name="{$pRoot}">
<xsl:copy-of select="$vXml1/*/*" />
<xsl:copy-of select="$vXml2/*/*" />
</xsl:element>
</xsl:template>
</xsl:stylesheet>
The code fails when $pXml1
contains space Ex. "a b c.xml"
How to solve it ??
Need some encode or not ?
When being passed a string, the document
function expects a URI. If your XSLT processor supports it, you can use the str:encode-uri
extension function from EXSLT to URI-encode your filename.
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