I need to determine开发者_运维百科 whether a phone number is valid before attempting to dial it. The phone call can go anywhere in the world.
What regular expression will match valid international phone numbers?
\+(9[976]\d|8[987530]\d|6[987]\d|5[90]\d|42\d|3[875]\d|
2[98654321]\d|9[8543210]|8[6421]|6[6543210]|5[87654321]|
4[987654310]|3[9643210]|2[70]|7|1)\d{1,14}$
Is the correct format for matching a generic international phone number. I replaced the US land line centric international access code 011 with the standard international access code identifier of '+', making it mandatory. I also changed the minimum for the national number to at least one digit.
Note that if you enter numbers in this format into your mobile phone address book, you may successfully call any number in your address book no matter where you travel. For land lines, replace the plus with the international access code for the country you are dialing from.
Note that this DOES NOT take into account national number plan rules - specifically, it allows zeros and ones in locations that national number plans may not allow and also allows number lengths greater than the national number plan for some countries (e.g., the US).
All country codes are defined by the ITU. The following regex is based on ITU-T E.164 and Annex to ITU Operational Bulletin No. 930 – 15.IV.2009. It contains all current country codes and codes reserved for future use. While it could be shortened a bit, I decided to include each code independently.
This is for calls originating from the USA. For other countries, replace the international access code (the 011 at the beginning of the regex) with whatever is appropriate for that country's dialing plan.
Also, note that ITU E.164 defines the maximum length of a full international telephone number to 15 digits. This means a three digit country code results in up to 12 additional digits, and a 1 digit country code could contain up to 14 additional digits. Hence the
[0-9]{0,14}$
a the end of the regex.
Most importantly, this regex does not mean the number is valid - each country defines its own internal numbering plan. This only ensures that the country code is valid.
^011(999|998|997|996|995|994|993|992|991| 990|979|978|977|976|975|974|973|972|971|970| 969|968|967|966|965|964|963|962|961|960|899| 898|897|896|895|894|893|892|891|890|889|888| 887|886|885|884|883|882|881|880|879|878|877| 876|875|874|873|872|871|870|859|858|857|856| 855|854|853|852|851|850|839|838|837|836|835| 834|833|832|831|830|809|808|807|806|805|804| 803|802|801|800|699|698|697|696|695|694|693| 692|691|690|689|688|687|686|685|684|683|682| 681|680|679|678|677|676|675|674|673|672|671| 670|599|598|597|596|595|594|593|592|591|590| 509|508|507|506|505|504|503|502|501|500|429| 428|427|426|425|424|423|422|421|420|389|388| 387|386|385|384|383|382|381|380|379|378|377| 376|375|374|373|372|371|370|359|358|357|356| 355|354|353|352|351|350|299|298|297|296|295| 294|293|292|291|290|289|288|287|286|285|284| 283|282|281|280|269|268|267|266|265|264|263| 262|261|260|259|258|257|256|255|254|253|252| 251|250|249|248|247|246|245|244|243|242|241| 240|239|238|237|236|235|234|233|232|231|230| 229|228|227|226|225|224|223|222|221|220|219| 218|217|216|215|214|213|212|211|210|98|95|94| 93|92|91|90|86|84|82|81|66|65|64|63|62|61|60| 58|57|56|55|54|53|52|51|49|48|47|46|45|44|43| 41|40|39|36|34|33|32|31|30|27|20|7|1)[0-9]{0, 14}$
This is a further optimisation.
\+(9[976]\d|8[987530]\d|6[987]\d|5[90]\d|42\d|3[875]\d|
2[98654321]\d|9[8543210]|8[6421]|6[6543210]|5[87654321]|
4[987654310]|3[9643210]|2[70]|7|1)
\W*\d\W*\d\W*\d\W*\d\W*\d\W*\d\W*\d\W*\d\W*(\d{1,2})$
(i) allows for valid international prefixes
(ii) followed by 9 or 10 digits, with any type or placing of delimeters (except between the last two digits)
This will match:
+1-234-567-8901
+61-234-567-89-01
+46-234 5678901
+1 (234) 56 89 901
+1 (234) 56-89 901
+46.234.567.8901
+1/234/567/8901
You can use the library libphonenumber from Google.
PhoneNumberUtil phoneNumberUtil = PhoneNumberUtil.getInstance();
String decodedNumber = null;
PhoneNumber number;
try {
number = phoneNumberUtil.parse(encodedHeader, null);
decodedNumber = phoneNumberUtil.format(number, PhoneNumberFormat.E164);
} catch (NumberParseException e) {
e.printStackTrace();
}
Modified @Eric's regular expression - added a list of all country codes (got them from xxxdepy @ Github. I hope you will find it helpful:
/(\+|00)(297|93|244|1264|358|355|376|971|54|374|1684|1268|61|43|994|257|32|229|226|880|359|973|1242|387|590|375|501|1441|591|55|1246|673|975|267|236|1|61|41|56|86|225|237|243|242|682|57|269|238|506|53|5999|61|1345|357|420|49|253|1767|45|1809|1829|1849|213|593|20|291|212|34|372|251|358|679|500|33|298|691|241|44|995|44|233|350|224|590|220|245|240|30|1473|299|502|594|1671|592|852|504|385|509|36|62|44|91|246|353|98|964|354|972|39|1876|44|962|81|76|77|254|996|855|686|1869|82|383|965|856|961|231|218|1758|423|94|266|370|352|371|853|590|212|377|373|261|960|52|692|389|223|356|95|382|976|1670|258|222|1664|596|230|265|60|262|264|687|227|672|234|505|683|31|47|977|674|64|968|92|507|64|51|63|680|675|48|1787|1939|850|351|595|970|689|974|262|40|7|250|966|249|221|65|500|4779|677|232|503|378|252|508|381|211|239|597|421|386|46|268|1721|248|963|1649|235|228|66|992|690|993|670|676|1868|216|90|688|886|255|256|380|598|1|998|3906698|379|1784|58|1284|1340|84|678|681|685|967|27|260|263)(9[976]\d|8[987530]\d|6[987]\d|5[90]\d|42\d|3[875]\d|2[98654321]\d|9[8543210]|8[6421]|6[6543210]|5[87654321]|4[987654310]|3[9643210]|2[70]|7|1)\d{4,20}$/
No criticism regarding those great answers I just want to present the simple solution I use for our admin content creators:
^(\+|00)[1-9][0-9 \-\(\)\.]{7,32}$
Force start with a plus or two zeros and use at least a little bit of numbers. White space, brackets, minus and point are optional, no other characters allowed.
You can safely remove all non-numbers and use this in a tel:
input. Numbers will have a common form of representation and I do not have to worry about being to restrictive.
I use this one:
/([0-9\s\-]{7,})(?:\s*(?:#|x\.?|ext\.?|extension)\s*(\d+))?$/
Advantages: recognizes + or 011 beginnings, lets it be as long as needed, and handles many extension conventions. (#,x,ext,extension)
This will work for international numbers;
C#:
@"^((\+\d{1,3}(-| )?\(?\d\)?(-| )?\d{1,5})|(\(?\d{2,6}\)?))(-| )?(\d{3,4})(-| )?(\d{4})(( x| ext)\d{1,5}){0,1}$"
JS:
/^((\+\d{1,3}(-| )?\(?\d\)?(-| )?\d{1,5})|(\(?\d{2,6}\)?))(-| )?(\d{3,4})(-| )?(\d{4})(( x| ext)\d{1,5}){0,1}$/
Here's an "optimized" version of your regex:
^011(9[976]\d|8[987530]\d|6[987]\d|5[90]\d|42\d|3[875]\d|
2[98654321]\d|9[8543210]|8[6421]|6[6543210]|5[87654321]|
4[987654310]|3[9643210]|2[70]|7|1)\d{0,14}$
You can replace the \d
s with [0-9]
if your regex syntax doesn't support \d
.
For iOS SWIFT I found this helpful,
let phoneRegEx = "^((\\+)|(00)|(\\*)|())[0-9]{3,14}((\\#)|())$"
Here is a regex for the following most common phone number scenarios. Although this is tailored from a US perspective for area codes it works for international scenarios.
- The actual number should be 10 digits only.
- For US numbers area code may be surrounded with parentheses ().
- The country code can be 1 to 3 digits long. Optionally may be preceded by a + sign.
- There may be dashes, spaces, dots or no spaces between country code, area code and the rest of the number.
A valid phone number cannot be all zeros.
^(?!\b(0)\1+\b)(\+?\d{1,3}[. -]?)?\(?\d{3}\)?([. -]?)\d{3}\3\d{4}$
Explanation:
^ - start of expression
(?!\b(0)\1+\b) - (?!)Negative Look ahead. \b - word boundary around a '0' character. \1 backtrack to previous capturing group (zero). Basically don't match all zeros.
(\+?\d{1,3}[. -]?)? - '\+?' plus sign before country code is optional.\d{1,3} - country code can be 1 to 3 digits long. '[. -]?' - spaces,dots and dashes are optional. The last question mark is to make country code optional.
\(?\d{3}\)? - '\)?' is to make parentheses optional. \d{3} - match 3 digit area code.
([. -]?) - optional space, dash or dot
$ - end of expression
More examples and explanation - https://regex101.com/r/hTH8Ct/2/
I have used this below:
^(\+|00)[0-9]{1,3}[0-9]{4,14}(?:x.+)?$
The format +CCC.NNNNNNNNNNxEEEE or 00CCC.NNNNNNNNNNxEEEE
Phone number must start with '+' or '00' for an international call. where C is the 1–3 digit country code,
N is up to 14 digits,
and E is the (optional) extension.
The leading plus sign and the dot following the country code are required. The literal “x” character is required only if an extension is provided.
I made the regexp for european phone numbers, and it is specific against dial prefix vs length of number.
const PhoneEuropeRegExp = () => {
// eu phones map https://en.wikipedia.org/wiki/Telephone_numbers_in_Europe
const phonesMap = {
"43": [4, 13],
"32": [8, 10],
"359": [7, 9],
"385": [8, 9],
"357": 8,
"420": 9,
"45": 8,
"372": 7,
"358": [5, 12],
"33": 9,
"350": 8,
"49": [3, 12],
"30": 10,
"36": [8, 9],
"354": [7, 9],
"353": [7, 9],
"39": [6, 12],
"371": 8,
"423": [7, 12],
"370": 8,
"352": 8,
"356": 8,
"31": 9,
"47": [4, 12],
"48": 9,
"351": 9,
"40": 9,
"421": 9,
"386": 8,
"34": 9,
"46": [6, 9],
};
const regExpBuilt = Object.keys(phonesMap)
.reduce(function(prev, key) {
const val = phonesMap[key];
if (Array.isArray(val)) {
prev.push("(\\+" + key + `[0-9]\{${val[0]},${val[1]}\})`);
} else {
prev.push("(\\+" + key + `[0-9]\{${val}\})`);
}
return prev;
}, [])
.join("|");
return new RegExp(`^(${regExpBuilt})$`);
};
alert(PhoneEuropeRegExp().test("+420123456789"))
It works pretty well with 00xx
and +xx
:
^(?:00|\+)(9[976]\d|8[987530]\d|6[987]\d|5[90]\d|42\d|3[875]\d|2[98654321]\d|9[8543210]|8[6421]|6[6543210]|5[87654321]|4[987654310]|3[9643210]|2[70]|7|1)\d{1,14}$
I only check for valid characters and allow up to 30 characters. Numbers that include an extension are also possible.
^[\+\(\s.\-\/\d\)]{5,30}$
Matches the following:
(0123) 123 456 1
555-555-5555
0049 1555 532-3455
123 456 7890
0761 12 34 56
+49 123 1-234-567-8901
+61-234-567-89-01
+46-234 5678901
+1 (234) 56 89 901
+1 (234) 56-89 901
+46.234.567.8901
+1/234/567/8901
There's obviously a multitude of ways to do this, as evidenced by all of the different answers given thus far, but I'll throw my $0.02 worth in here and provide the regex below, which is a bit more terse than nearly all of the above, but more thorough than most as well. It also has the nice side-effect of leaving the country code in $1 and the local number in $2.
^\+(?=\d{5,15}$)(1|2[078]|3[0-469]|4[013-9]|5[1-8]|6[0-6]|7|8[1-469]|9[0-58]|[2-9]..)(\d+)$
A simple version for european numbers, that matches numbers like 0034617393211 but also long ones as 004401484172842.
^0{2}[0-9]{11,}
Hope it helps :·)
public static boolean validateInternationalPhoneNumberFormat(String phone) {
StringBuilder sb = new StringBuilder(200);
// Country code
sb.append("^(\\+{1}[\\d]{1,3})?");
// Area code, with or without parentheses
sb.append("([\\s])?(([\\(]{1}[\\d]{2,3}[\\)]{1}[\\s]?)|([\\d]{2,3}[\\s]?))?");
// Phone number separator can be "-", "." or " "
// Minimum of 5 digits (for fixed line phones in Solomon Islands)
sb.append("\\d[\\-\\.\\s]?\\d[\\-\\.\\s]?\\d[\\-\\.\\s]?\\d[\\-\\.\\s]?\\d[\\-\\.\\s]?");
// 4 more optional digits
sb.append("\\d?[\\-\\.\\s]?\\d?[\\-\\.\\s]?\\d?[\\-\\.\\s]?\\d?$");
return Pattern.compile(sb.toString()).matcher(phone).find();
}
The international numbering plan is based on the ITU E.164 numbering plan. I guess that's the starting point to your regular expression.
I'll update this if I get around to create a regular expression based on the ITU E.164 numbering.
This Regex Expression works for India, Canada, Europe, New Zealand, Australia, United States phone numbers, along with their country codes:
"^(\+(([0-9]){1,2})[-.])?((((([0-9]){2,3})[-.]){1,2}([0-9]{4,10}))|([0-9]{10}))$"
This works for me, without 00, 001, 0011 etc prefix though:
/^\+*(\d{3})*[0-9,\-]{8,}/
Try this, it works for me.
^(00|\+)[1-9]{1}([0-9][\s]*){9,16}$
^\+[1-9]\d{10,14}$
This will match "e164 phone numbers"
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