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How to best approach rounding up decimals in C#

开发者 https://www.devze.com 2022-12-17 05:12 出处:网络
I\'ve decimal value 18.8. Values that are stored in this variable can be of any kind. For example it can be 1.0000000 or 1.00004000 or 5.00000008.

I've decimal value 18.8. Values that are stored in this variable can be of any kind. For example it can be 1.0000000 or 1.00004000 or 5.00000008. I would like to write a method so that I can pass decimal to it and get rounded up string. This wouldn't be a problem if I would know decimal places I would like to get. But what I would like to get is:

When it's 1.0000000 it should return 1.

If it's 1.00004000 it should return 1.00004.

When it's 5.00000008 it should return 5.00000008. So basically it should find all 0 that are behind last digit different then 0 and cut it off.

How should I approach it? What's the best method? I'm getting this value from SQL and put it in decimal variable but then i would like to display it and having 5.0000000 when it could be displayed as 5 is a bit overkill for me.

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Hope I could get some nice suggestions.


AFAIK, ToString( "0.##" ) will do, just increase number of # so that your value won't round up. E.g.:

decimal d = 1.999m;
string dStr = d.ToString("0.###");

This will generate "1,999" string (delimiter depends upon used culture).

As a result, you can use common very long formatting string: "0.############################" - to format all your values.


So trim the zeroes from the end.

decimal d = 1.999m;
string dStr = d.ToString().TrimEnd('0').TrimEnd('.');


You can also use string.Format and here's the documentation of the different possible formats but I like Johan Sheehans cheat sheet more as a quick reference.

decimal number=4711.00004711m;
4711.00004711
string.Format("{0:0.#############}",number);
"4711,00004711"
number=42;
42
string.Format("{0:0.#############}",number);
"42"


Take a look at Jon Skeets article: http://www.yoda.arachsys.com/csharp/floatingpoint.html

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