I have statements like this all over my code:
LogWrite (String1开发者_如何学Python,
String2,
L"=======format string======",
...
);
I want to change each of these to:
LogWrite (String1,
String2,
L"format string",
...
);
I'm trying to write the regexp required to do this using the Emacs function query-replace-regexp, but not much success yet. Help please!
UPDATE: 1) In case it is not clear, this question is emacs specific.
2) I would like to match the entire code chunk starting from Log... ending at );
3) I used the following reg-exp to match the code chunk:
L.*\n.*\n.*==.*;
I used re-builder to match this regexp. the \n is used because I found that otherwise emacs would stop matching at the new line. The problem is that I don't know how to select the format string and save it to use it in the replace regexp - hence the ==.* part in the regexp. That needs to be modified to save the format string.
If you don't have multiple (or escaped) double quotes in those format string lines, you can
//replace
L"=+(.*)=+"
//with
L"\1"
Update: Removed the lazy quantifier (thanks @tim). Make sure that the regex is not multiline; the greedy *
will lead to pretty bad results if .
matches new lines
A great tool to figure out emacs regular expressions is:
M-x re-builder
A brief description from the documentation:
When called up
re-builder' attaches itself to the current buffer which becomes its target buffer, where all the matching is done. The active window is split so you have a view on the data while authoring the RE. If the edited expression is valid the matches in the target buffer are marked automatically with colored overlays (for non-color displays see below) giving you feedback over the extents of the matched (sub) expressions. The (non-)validity is shown only in the modeline without throwing the errors at you. If you want to know the reason why RE Builder considers it as invalid call
reb-force-update' ("\C-c\C-u") which should reveal the error.
It comes built into Emacs (since 21)
And for the syntax of Emacs regular expressions, you can read these info pages:
- Syntax of Regular Expressions
- Backslash in Regular Expressions
/={7}(.*)={6}/\1/
this should do.
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