Overlapping regular expressions part II

In this question I asked for a regex to turn /abc/def/ghi into {/abc/def/ghi, /def/ghi, /ghi}. The answer was to use lookahead with 开发者_JAVA百科the expression (?=(/.*)).

Is there a regex to capture from the same string {/abc, /abc/def, /abc/def/ghi}? (Order is not important.)

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Ok, here's a solution that works for your one and only test case, though I haven't found a way to group it into one nice group:

Matcher m = Pattern.compile("((?<=(^.*))(/[^/]*))").matcher("/abc/def/ghi");
while (m.find()) {
   System.out.println(m.group(2) + m.group(3));
}

It essentially finds each /xxx substring as they appear but then also concatenates everything before that match. This works for your test case but might have limitations for more complex cases.

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This will do what you want:

(?<=(/.*)\b)