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Obj-c generate a random float(or double) number between 0 and ∏ * 2

开发者 https://www.devze.com 2023-04-12 20:24 出处:网络
I am trying to generate a random float(or开发者_StackOverflow社区 double) number between 0 and ∏ * 2.

I am trying to generate a random float(or开发者_StackOverflow社区 double) number between 0 and ∏ * 2.

All I can find is how to generate a random float number between 0 and 2.. but that leaves out .28 possibilities. (roughly)

can anyone help?

Thanks


You can make a random number between 0 and 1 and then multiply by 2pi. That should do the trick for you.


This should do it:

float f = arc4random() / ((pow(2, 32)-1)) * M_PI*2;

arc4random returns values between 0 and 2^32-1. Dividing by that number gives the range 0..1. Multiply by the range you need (2pi) gives the final range 0..2pi


Couldn't you just generate a random float between 0.0 and 1.0, then multiply it by 2PI?

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