Radio button checked issue

My question was about the browser matter as far as I see. I asked is there any solution to tell browser to move checked="checked" between radio buttons. I thought there will be a quick solution for this but this case is just confusing. I changed my code now. I use select list element now.

I have a form, and I get the actual settings with php, but the matter is this:

When the radio button 1 comes checked="checked" if that is actual, after it when I change to other option in post I get checked="checked"'s value, I was wondering is there a solution for this or Javascript is needed something like onclick"this.checked otherone uncheck" ?

if($type==1) { $like = 'checked="checked"'; } else { $ref='checked="checked"'; }

<form method="post" acti开发者_StackOverflow社区on="process.php" id="fbform" name="fbform">
<div class="radio">
<p>Like button: </p>
<input type="radio" name="tipi" <?=$like?> value="1" />
</div>
<div class="radio1">
<p>Link:</p> 
<input type="radio" name="tipi" <?=$ref?> value="2" />
</div>
</form>

Process.php file code

<?php
$mysql->update('settings'," tipi='".$_POST['tipi]."' ");
?>

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checked is a marker tag - it does not care , as long if the word 'checked' is there.

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Here is what I would do:

<div class="radio">
  <p>Like button: </p>
  <input type="radio" name="tipi" id="tipi1" value="1"<?php if ($type == 1) echo ' checked="checked"'; ?> />
</div>
<div class="radio1">
  <p>Link:</p> 
  <input type="radio" name="tipi" id="tipi2" value="2"<?php if ($type != 1) echo ' checked="checked"'; ?> />
</div>

I have changed the id's because you had two elements with the same id, which will never work, even if those elements are part of the same group.

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You can do better with this. Also, IDs are used only for CSS or JS, and moreover must be UNIQUE.

<div class="radio">
<p>Like button: </p>

<input type="radio" name="tipi" id="tipi" <?php echo ($type == '1')?'checked="checked"' : '';?> value="1" />

</div>

<div class="radio1">

<p>Link:</p> 
<input type="radio" name="tipi" id="tipi2" <?php echo ($type=='2')?'checked="checked"' : '';?> value="2" />

</div>

Then you access them in php

$tipi = $_POST['tipi']; //either 1 or 2

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you need very simple changes in your code..See below code:

first of all you need to define variables at very top of the page/Code:

$like = ""; 
$ref = "";

Now your code will working good as per my knowledge..

Thanks.

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Ghostology: Not sure about your query ... But all I can do is explain you the working of the radio button.

suppose there are two radio buttons inside a form:

<input type="radio" name="radioTest" value="1" checked />
<input type="radio" name="radioTest" value="0"  />

Here checked specifies the button which will be checked(or turned on) during page load.

Now suppose we check the second button and submit this form, now we get the value 0 against the parameter 'radioTest' as radio button with value 0 is checked.

Now when page loads again with some value of radio buttons. You would want the proper radio button to be checked. For this case I guess u can use if/else condition like: <% if(radioTest.value == 1){ %> <% }else{ %> <% } %>