the meaninings of two ** for an iterator

In the f开发者_运维问答ollowing code segment

vector<SceneObject *> sceneObjs;
vector<SceneObject *>::iterator iter;

iter = sceneObjs.begin();
while (iter != sceneObjs.end()){
  cout << **iter <<endl;
  iter++;
}

why **iter has two *s ?

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The first * dereferences the iterator, giving a SceneObject * pointer. The second * dereferences this SceneObject * pointer to the SceneObject itself.

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Because *iter is a SceneObject *& - a SceneObject pointer. You need to dereference it to get to the real SceneObject.

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Because *iter returns a SceneObject* which will then be again dereferenced by the second *.

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The first * returns the vale in the iterator, a SceneObject* pointer. The second * deferences that pointer, giving a SceneObject. I suspect there's an overload for << that renders the SceneObject` to a stream.