Here's my code:
开发者_如何学Gocurl -u "u:d" --data-urlencode "status=`echo $@|tr ' ' '+'|tr '&' '%26'`" "http://twitter.com/statuses/update.json"
But when it goes to twitter, the '&' turns into '%'. What am I doing wrong? Thanks!
tr
performs individual character replacement.
It replaces &
with %
because that's what you told it to do.
You want something like sed
which does more than just character-by-character substitution.
sed "s/\&/\%26/g"
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