Nested for loops with if statement gives too many answers

I would like to compare one textfile, line by line, with another textfile, to find out how many times the same text appears in text file 2. The problem is that I am getting too many loops. How do I solve this?

#!/bin/bash
# Read text file
echo "Enter file name"
read fname

# Read text file
echo "Enter file name"
read fcheck

# rm out2.txt
c1=0

for i in $(cat $开发者_如何学Cfname);

do
    for j in $(cat $fcheck);
    do

        if [[ $i == $j ]]
        then
            let c1=c1+1;
        fi

    done

    echo $c1 # >> out2.txt
    c1=0;
done

---

The problem with your for loops is that they read the files word-by-word. Instead, do something like this:

while read line_a
do
    while read line_b
    do
        if [ "$line_a" = "$line_b" ]
        then
            let c1=c1+1;
        fi
    done < "$fcheck"

    echo $c1
    c1=0;
done < "$fname"

Make it a habit to enclose variables in quotation marks, like "$var", to avoid problems with spaces.

---

comm is really what you need:

common_lines=$(comm -12 <(sort "$fname") <(sort "$fcheck"))
printf "%d common lines:\n" $(wc -l <<< "$common_lines")
echo "$common_lines"

---

I'd do

 fname=file1.txt
 fcheck=file2.txt

 cat "$fname" | while read line 
 do
     echo -e "$(fgrep -c "$line" "$fcheck")\t$line"
 done