MySQL How to SELECT data from table which recorded today?

Use PHP and MySQL. In my table, there is date field (datetime) recorded by NOW() sql function. Example val开发者_JS百科ue of data in this field is 2010-10-07 10:57:36. How can I SELECT all data which day-month-year is today. I try to use code as below:

  SELECT * FROM table WHERE date=????

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Try this:

SELECT * FROM table WHERE date > CURDATE();

CURDATE() will return the current date as 2011-10-07 which will be cast to 2011-10-07 00:00:00 when comparing datetimes to it.

Note that if you use DATE(date) = CURDATE() you will run a date conversion for every row in the table, which will be really bad for your perfomance if you have many rows and/or you need to run the query often. Also make sure you have an index on date, otherwise both methods will be even slower.

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SELECT * FROM table where DATE(date)=CURDATE()

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SELECT * FROM tableName WHERE DATE(fieldDate) = DATE(NOW());

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The date_format function allows you to easily switch between various granularities:

Select everything from the same day:

select * from table 
where date_format(date, '%Y-%m-%d') = date_format(now(), '%Y-%m-%d');

From the same month:

select * from table 
where date_format(date, '%Y-%m') = date_format(now(), '%Y-%m');

From the same year:

select * from table 
where date_format(date, '%Y') = date_format(now(), '%Y');

From the same hour:

select * from table 
where date_format(date, '%Y-%m-%d %H') = date_format(now(), '%Y-%m-%d %H');

and so on.

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Try this

SELECT * FROM table WHERE DATE(my_date)=DATE(now())

my_date -> column name

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SET @day = '2017-12-12' ;

SELECT * FROM table WHERE dateColumn BETWEEN DATE(@day) AND DATE_ADD(DATE(@day), INTERVAL 1 DAY ) ;

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use something like this it exactly works on my code(access database):

select * from Table t where t.column>=Date() and t.column< Date() + 1

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use between.

select * from table date between '2010-10-06' and '2010-10-08';