开发者

PHP - Concatenating two variables

开发者 https://www.devze.com 2023-04-11 04:27 出处:网络
I\'m a newbie stumped on the following. If I\'m including an external file on a page that contains the following variable:

I'm a newbie stumped on the following. If I'm including an external file on a page that contains the following variable:

$blurb_78 = "Lorem ipsum dolor.";

How can I echo $blurb_78 on the local page? (where the 78 part is a generated article ID set to a variable labeled, $id)

The following doesn't work:

echo $blurb_.$id;

Th开发者_StackOverflow中文版anks much for your help.


I think you mean a variable variable name like it is mentioned at the Variable variables page on the PHP site. In your case this should work fine:

echo ${'blurb_'.$id}; 

But I highly doubt your approach on this one.


Try making an array:

$blurb = array();

$blurb[78] = "Lorem ipsum";

echo $blurb[$id];


You should use an associative array instead of variables in your case.

Check this article in PHP official documentation:

  • http://php.net/manual/es/language.types.array.php


This is your answer:

 echo '$blurb_'.$id;

Still, an associative array is the way to go.


Try

<?php
$blurb_78 = 'Lorem ipsum dolor.';
$id = 78;
echo ${'blurb_'.$id};
?>


echo ${'blurb_'.$id};

Demo

Read more on the variable variables article.


This should work for concatenating two variables:

echo ${'blurb_'.$id}
0

精彩评论

暂无评论...
验证码 换一张
取 消

关注公众号