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Django cannot import name x [duplicate]

开发者 https://www.devze.com 2023-04-11 04:03 出处:网络
This question already has answers here: What can I do about "ImportError: Cannot import name X" or "AttributeError: ... (most likely due to a circular import)"?
This question already has answers here: What can I do about "ImportError: Cannot import name X" or "AttributeError: ... (most likely due to a circular import)"? (17 answers) Closed 3 years ago.

I got an error I don't understand !

cannot import name Item

In my model, I have items. These items are required for actions. But some of these items have an effect on actions :

items

from django.db import models
from effects.models import Effect

class Type(models.Model):
    name = models.CharField(max_length=200)

    def __unicode__(self):
         return self.name

class Item(models.Model):
    name = models.CharField(max_length=200)
    description = models.CharField(max_length=200)
    type = models.ForeignKey(Type)
    quality = models.IntegerField()
    effects = models.ManyToManyField(Effect,through='ItemEffect',blank=True)
    item_requirement = models.ManyToManyField('self',through='ItemCraft',symmetrical=False,blank=True)
points = models.IntegerField()

    def __unicode__(self):
        return self.name

class Food(Item):
    ap = models.IntegerField()

class Tool(Item):
    durability = models.IntegerField()

[....]

class ItemEffect(models.Model):
    item = models.ForeignKey(Item)
    effect = models.ForeignKey(Effect)

def __unicode__(self):
    return self.item.name+':'+str.lower(self.effect.name)

class Meta:
    verbose_name_plural = 'items effects'

class ItemCraft(models.Model):
    item = models.ForeignKey(Item,related_name='%(class)s_item_crafted')
    item_requirement = models.ForeignKey(Item,related_name='%(class)s_item_required')
    number = models.IntegerField()

    def __unicode__(self):
        return self.item.name+' requires '+str.lower(self.item.name)+'('+self.number+')'

    class Meta:
        verbose_name_plural开发者_开发百科 = 'items crafts'

actions

from django.db import models
from items.models import Item

class Action(models.Model):
    name = models.CharField(max_length=200)
    description = models.CharField(max_length=200)
    pa = models.IntegerField()

    def __unicode__(self):
        return self.name

class CraftAction(Action):
    item = models.ForeignKey(Item)

    def __unicode__(self):
        return self.item.name+'\'s craft'

    class Meta:
        verbose_name_plural = 'crafts actions'

effects

from django.db import models
from actions.models import Action

class Effect(models.Model):
    action = models.ForeignKey

class ApEffect(Effect):
    ap = models.IntegerField()


There is a circular import in your code, that's why the Item can't be imported in action.

You can solve the problem by removing the import of a class in one of your files, and replacing it with a string containing the name of the class, as explained in the documentation. For example :

effects = models.ManyToManyField('effects.Effect',through='ItemEffect',blank=True)


Like madjar suggested, there is likely a circular import in your code. If you're having trouble finding out where the circle is (which modules and imports are involved), you can use the traceback option to get an idea of where the problem lies:

python manage.py validate --traceback

Edit - Validate is deprecated from django 1.7. So please run the following command -

python manage.py check --traceback


Try to import Locally your model instead of as public one, Example

def sample_function():
    from effects.models import Effect # import within function or class

or import model as String -> 'APP_NAME.MODEL_NAME'

pay_methods = models.ManyToManyField('payment_app.AllowedPayMethod')


This was the first post that came up on Google so I will post this alternative cause of error.

In my code there was no circular imports, I solved this problem by manually deleting all .pyc files in my project. Apparently restarting the application wasn't recompiling my code.


Similar situation to Pythonator - I had an alternate cause for the same error message.

In my case, I had forgotten to activate the virtual environment I set up for my project and was trying to run the server. After activating the environment and running the server again I had no issues.

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