开发者

Pass by reference problem with PHP 5.3.1 [duplicate]

开发者 https://www.devze.com 2022-12-16 15:34 出处:网络
This question already has answers here: mysqli bind_param() expected to be a reference, value given (3 answers)
This question already has answers here: mysqli bind_param() expected to be a reference, value given (3 answers) Closed 9 months ago.

Ok, this is a weird problem, so please bear with me as I explain.

We upgraded our dev servers from PHP 5.2.5 to 5.3.1.

Loading up our code after the switch, we start getting errors like:

Warning: Parameter 2 to mysqli_stmt::bind_param() expected to be a reference, value given in /home/spot/trunk/system/core/Database.class.php on line 105

the line mentioned (105) is as follows:

call_user_func_array(Array($stmt, 'bind_param'), $passArray);

we changed the line to the following:

call_user_func_array(Array($stmt, 'bind_param'), &$passArray);

at this point (because allow_call_time_pass_reference) is turned off, php throws this:

Deprecated: Call-time pass-by-reference has been deprecated in /home/spot/trunk/system/core/Database.class.php on line 105

After trying to fix this for some time, I broke down and set allow_call_time_pass_reference to on.

That got rid of the Deprecated warning, but now the Warning: Parameter 2 to mysqli_stmt::bind_param() expected to be a reference warning is throwing every time, with or without the referencing.

I have zero clue how to fix this. If the target method was my own, I would just reference the incoming vars in the func declaration, but it's a (relatively) native method (mysqli).

Has anyone开发者_运维技巧 experienced this? How can I get around it?

Thank you.


I just experienced this same problem, calling bind_param via call_user_func_array and passing an array of parameters. The solution is to modify the values in the array to be referenced. It's not elegant but it works.

call_user_func_array(array($stmt, 'bind_param'), makeValuesReferenced($passArray));

function makeValuesReferenced($arr){
    $refs = array();
    foreach($arr as $key => $value)
        $refs[$key] = &$arr[$key];
    return $refs;

}


You are passing an array of elements ($passArray). The second item inside the passed array needs to be a reference, since that is really the list of items you are passing to the function.


Actually, be aware that there is a bug with PHP 5.3.1 concerning references and all call family of functions:

PHP Bugs #50394: Reference argument converted to value in __call

The behavior you are seeing might be a result of this bug and any attempt to fix it code wise may cause problems in the long run.

The problem has been fixed in the SVN version of PHP. Until 5.3.2 is released, you may compile a new version for use, or downgrade to an earlier version.


We were experiencing this same problem with this code:

call_user_func(array($strCartHandler, 'CartPurchaseEvent'), $strCartEvent, $objToUser, null, $this);

My solution was to just skip call_user_func altogether and do this:

$strCartHandler::CartPurchaseEvent($strCartEvent, $objToUser, null, $this);


I think what is deprecated is passing a reference through a function. In the function definition you do something like:

function(&$arg) {

}

This doesn't help you much but you probably need not pass the reference anyway. I guess you could try a wrapper function.

function wrapper($stmt, &$passArray) {
    call_user_func_array($stmt, $passArray);
}


I think the mysqli_bind_param() and mysqli_bind_result() functions are very awkward to use. I've encountered the same difficulty as you describe using them in combination with call_user_func_array()

My workaround was to stop using mysqli and instead use PDO_mysql. It has a much easier usage:

$pdoStmt->execute( $passArray );


This will helps:

<?php
call_user_func_array(Array($stmt, 'bind_param'), array(&$passArray));

function bind_param ($val)
{
    $val = (is_array($val)) ? $val[0] : $val;

    // operations...
}

?>


The second paramer Must be an array. apparently this was only enforced in 5.3


I've got a similar problem, the current code didnt work:

$query="Select id,name FROM mytable LIMIT ?,?";
$params=Array('ii');
array_push($params,$from_var);
array_push($params,$to_var);
...
$stmt=$link->prepare("$query");
$ref=new ReflectionClass('mysqli_stmt');
$method=$ref->getMethod("bind_param");
$method->invokeArgs($stmt,$params);
...

It told that "Parameter 2 to mysqli_stmt::bind_param() expected to be a reference, value given"

And then, in despair, I've tried to take $from_var and $to_var in quotes. And it worked!

$params=Array('ii');
array_push($params,"$from_var");
array_push($params,"$to_var");

Hope, it will help somebody, good luck :)

0

精彩评论

暂无评论...
验证码 换一张
取 消