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Selecting all for the week xx, not working properly php

开发者 https://www.devze.com 2023-04-10 07:05 出处:网络
Ok this is what i have: function getFirstDayOfWeek($iYear, $iWeekNumber) { if ( is_null($iYear) ) $iYear = date(\'Y\');

Ok this is what i have:

function getFirstDayOfWeek($iYear, $iWeekNumber)
{
    if ( is_null($iYear) ) $iYear = date('Y');
    if ( $iWeekNumber < 10 ) $iWeekNumber = '0'.$iWeekNumber;

    $iTime = strtotime($iYear.'W'.$iWeekNumber);

    return $iTime;
}

$firstdayofweek = getFirstDayOfWeek($data['year'], $data['week']);
$mDate = date('m', $firstdayofweek);
$dDate = date('d', $firstdayofweek);
$min = mktime(0, 0, 0, $mDate, $dDate, $data['year']);
$max = mktime(23, 59, 59, $dDate, $dDate+6, $data['year']);

Where it later does:

SELECT id
FROM training_activities
WHERE date time >= {$min} 
  AND time <= {$max}

As you may now until now, the times are saved in unix timestamp.

This code is not working p开发者_StackOverflow社区roperly.

Lets say $data year is 2011 and week 39.

This shows me dates from 26/09-04/10, 8 days, while the week 39 is 29/09 - 02/10

How can i make it select and show weeks right?


The $max month was using $dDate instead of $mDate; the following works:

<?php

function getFirstDayOfWeek($iYear, $iWeekNumber)
{
    if ( is_null($iYear) ) $iYear = date('Y');
    if ( $iWeekNumber < 10 ) $iWeekNumber = '0'.$iWeekNumber;

    $iTime = strtotime($iYear.'W'.$iWeekNumber);

    return $iTime;
}

for ($i = 1; $i <= 52; $i++) {
    $firstdayofweek = getFirstDayOfWeek(2011, $i);
    $mDate = date('m', $firstdayofweek);
    $dDate = date('d', $firstdayofweek);
    $min = mktime(0, 0, 0, $mDate, $dDate, 2011);
    $max = mktime(23, 59, 59, $mDate, ($dDate+6), 2011);
    echo date('m/d/Y',$min)." - ".date('m/d/Y',$max)." ($dDate - ".($dDate+6).")\n";
}

?>

http://codepad.org/7hMJQFhq

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