get all lines of a continuation line in traceback

Is it possible to get all lines of a continuation line in a traceback?

Example:

#! /usr/bin/env python
def function_with_long_name(foo, bar):
  raise Exception('problem?'开发者_JS百科)
function_with_long_name('very_important_value',
  'meaningless_value')

Output:

$ ./test.py 
Traceback (most recent call last):
  File "./test.py", line 5, in <module>
    'meaningless_value')
  File "./test.py", line 3, in function_with_long_name
    raise Exception('problem?')
Exception: problem?

Note that it prints only the last line of the continuation line.

I would like to have all lines of the continuation line, something like this:

$ ./test.py 
Traceback (most recent call last):
  File "./test.py", line 5, in <module>
    function_with_long_name('very_important_value',
      'meaningless_value')
  File "./test.py", line 3, in function_with_long_name
    raise Exception('problem?')
Exception: problem?

Is this possible?

I have looked at the traceback module, but the values it returns are already truncated.

Example:

#! /usr/bin/env python
import traceback
def function_with_long_name(foo, bar):
  print traceback.extract_stack()
function_with_long_name('very_important_value',
  'meaningless_value')

Output:

$ ./test.py 
[('./test.py', 6, '<module>', "'meaningless_value')"), ('./test.py', 4, 'function_with_long_name', 'print traceback.extract_stack()')]

---

Someone appears to have just opened Python issue 12458 about this. Suggest you follow along there.