I want to optimize this query (since subqueries aren't fast in general), but I'm lost because I cannot rewrite this using joins which will be better for performance, can you help mi with this?
SELECT id, company, street, number, number_addition, postalc开发者_Python百科ode, telephone
FROM clients
WHERE (postalcode BETWEEN '1000' AND '9000') AND street = (
SELECT DISTINCT street FROM clients WHERE (postalcode BETWEEN '1000' AND '9000') AND postalcode <= (
SELECT MIN(postalcode) FROM clients WHERE street = 'Main Street' AND (postalcode BETWEEN '1000' AND '9000'))
ORDER BY postalcode DESC LIMIT 1, 1)
ORDER BY postalcode DESC, street DESC, number DESC, number_addition DESC, telephone DESC
LIMIT 1
Thanks for your time guys.
SELECT DISTINCT street ORDER BY postalcode
doesn't make sense (and I think isn't valid ANSI SQL), unless postalcode
is functionally-dependent on street
—which I don't think it is, as your get-lowest-postalcode-on-Main-Street inner subselect wouldn't make sense if it was. MySQL will let you get away with it but the results will be inconsistent. What are you trying to say here?
I don't think this should be particularly slow since what you have isn't a dependent subquery; the subqueries are executed only once and not repeatedly for each outer row. You could rewrite it as three separate queries—
- get lowest postalcode on Main Street;
- get street with second-highest postal code lower than (1) (inconsistently);
- get details of clients on street (2).
with no difference in execution. (Indeed, it might be better to do so for clarity.)
You could rewrite these as joins, using self-left-joins-on-less-than-is-null to get the minima/maxima, but I don't think you'd gain anything by it for this example and it would get very messy given the two levels of joining and the second-highest requirement. Is this query particularly slow in practice? What does the EXPLAIN
look like? Have you indexed postalcode
and street
?
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