开发者

getResource with parent directory reference

开发者 https://www.devze.com 2023-04-10 00:20 出处:网络
I have a java app where I\'m trying to load a text file that will be included in the jar. When I do getClass().getResource(\"/a/b/c/\"), it\'s able to create the URL for that path and I can print it

I have a java app where I'm trying to load a text file that will be included in the jar.

When I do getClass().getResource("/a/b/c/"), it's able to create the URL for that path and I can print it out and everything looks fine.

However, if I try getClass().getResource(/a/b/../"), then I get a null URL back.

It seems to not like the 开发者_运维知识库.. in the path. Anyone see what I'm doing wrong? I can post more code if it would be helpful.


The normalize() methods (there are four of them) in the FilenameUtils class could help you. It's in the Apache Commons IO library.

final String name =  "/a/b/../";
final String normalizedName = FilenameUtils.normalize(name, true); // "/a/"
getClass().getResource(normalizedName);


The path you specify in getResource() is not a file system path and can not be resolved canonically in the same way as paths are resolved by File object (and its ilk). Can I take it that you are trying to read a resource relative to another path?

0

精彩评论

暂无评论...
验证码 换一张
取 消