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while loop within foreach

开发者 https://www.devze.com 2023-04-09 20:12 出处:网络
I\'ve got a form with questions which gets answered.Then o开发者_如何学Gon the following page I\'m trying to validate the questions to see if the answer is correct or not because eventually I must wor

I've got a form with questions which gets answered. Then o开发者_如何学Gon the following page I'm trying to validate the questions to see if the answer is correct or not because eventually I must work out a percentage for the test.

$tid1 = $_SESSION['tid'];
$departmentid = $_SESSION['deptid'];
$userid = $_SESSION['userid'];

foreach($_POST['question'] as $key => $answer) {
    include 'datalogin.php';
    mysql_query("INSERT INTO ex_answer (id,class_name,testname,name,percentage,qnr,answer_chosen,points_scored,result)
VALUES ('0','$departmentid','$tid1','$userid','0','$key','$answer[0] $answer[1] $answer[2] $answer[3] $answer[4] $answer[5] $answer[6] $answer[7] $answer[8]','0','0')");

    $sql1="SELECT * FROM ex_question WHERE test_name = '$tid1' AND q_nr = '$key'";
    $result1=mysql_query($sql1);
    while($row1 = mysql_fetch_array($result1)) {
        $q_nr=$row1['q_nr'];
        echo $q_nr;
    }
}

The problem is (I think) that it is not selecting the question number q_nr = '$key' correctly from the table because echo $q_nr gives no output


If you are getting a valid result (Test the sql in your Database client ) then you should just use the following to access it as an associative array:

mysql_fetch_assoc($result1); 

instead of the mysql_fetch_array() or use mysql_fetch_array($result1, MYSQL_ASSOC)

Test what is being returned to you, comment out your while loop and then do:

$row1 = mysql_fetch_array($result1);
print_r($row1);

before you while loop add the following for validation:

if (!$result1) {
    die('Could not query:' . mysql_error());
}


Use mysql_fetch_assoc to be able to use column name indexes on returned array.


You can also output the SQL and test it on the DB, that will show that you are getting the expected results

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